Algebra 2 Help

Algebra 2 is not the easiest part of math but getting help with algebra 2 is easier than ever with online math helpers. Get all the help you need on your computer screen any time you want. Help in algebra 2 is available freely on the internet and students will benefit from the online tools and resources used to teach the subject. There are any number of math help sites which students can choose from based on their preference and compatibility. Algebra 2 help covers all the aspects of the subject including practice problems and algebra 2 word problems. Online math algebra 2 help uses interactive tools like whiteboards and games to hold a students attention and make their concepts clear.

Help With Algebra 2

Algebra 2 help online is one the easiest ways to get help in math without compromising on quality. Online math solvers have a wealth of experience in helping students of various grades understand and develop an interest in algebra. Get help on algebra 2 homework with online math solvers who will help solve your problems and correct your work as well. Math algebra 2 help is a great way for students who know algebra well to improve their knowledge of the subject and move on to slightly higher level concepts if they want.

Solved Examples

Question 1: The difference of two numbers is 12. Find the numbers, if three times one of these numbers exceeds two times the other number by 10.

Solution:
Let the numbers be x and y

Step 1:

The difference of numbers is 12

=> x - y = 12                                      .........................................(1)

and
Three times one of these numbers exceeds two times the other number by 10.

=> 3 times one number - 2 times other = 10

=> 3x - 2y = 10                                ..........................................(2) 

Step 2:

(1) => x = 12 + y                             .......................................... (3)

Put x = 12 + y  in equation (2)

=> 3(12 + y) - 2y = 10

=> 36 + 3y - 2y = 10

=> y = 10 - 36 = - 26

Step 3:

Put y = - 26 in equation (3)

=> x = 12 + (- 26)

=> x = 12 - 26 = -14

Answer: x = - 14 and y = - 26

 

Question 2: Solve the equation for x, 32x - 46 = 12x + 20
Solution:
Given, 32x - 46 = 12x + 20

Solve for x,

32x - 46 = 12x + 20

Subtract 12x from both sides

=> 32x - 46 - 12x = 12x + 20 - 12x

=> 20x - 46 = 20

Add 46 to each side of the equation

=> 20x - 46 + 46 = 20 + 46

=> 20x = 66

Divide each side by 20

=> x = $\frac{66}{20}$

or x = $\frac{33}{10}$
 

Question 3: Find the factor of x2 - 13x + 42
Solution:
Given quadratic equation, x2 - 13x + 42

Factorized the equation

x2 - 13x + 42 = x2 - 7x - 6x + 42

= x(x - 7) - 6(x - 7)

= (x - 6)(x - 7)

=> x2 - 13 + 42 = (x - 6)(x - 7)  
 

Question 4: What is the value of $\frac{2^8}{2^5}$ x $\frac{3^4}{3^7}$
Solution:
$\frac{2^8}{2^5}$ x $\frac{3^4}{3^7}$ = 28 - 5 x 34 - 7

[Using law of indices, $\frac{x^m}{x^n}$ = xm - n  ]

=> $\frac{2^8}{2^5}$ x $\frac{3^4}{3^7}$ = 23 x 3- 3

= $\frac{2^3}{3^3}$

= $\frac{8}{27}$

=> $\frac{2^8}{2^5}$ x $\frac{3^4}{3^7}$ = $\frac{8}{27}$